w32: Make qemu_vfree() accept NULL like the POSIX implementation
On POSIX, qemu_vfree() accepts NULL, because it's merely wrapper around free(). As far as I can tell, the Windows implementation doesn't. Breeds bugs that bite only under Windows. Make the Windows implementation behave like the POSIX implementation. Signed-off-by: Markus Armbruster <armbru@redhat.com> Reviewed-by: Kevin Wolf <kwolf@redhat.com> Signed-off-by: Stefan Hajnoczi <stefanha@redhat.com>
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				| @ -71,7 +71,9 @@ void *qemu_vmalloc(size_t size) | ||||
| void qemu_vfree(void *ptr) | ||||
| { | ||||
|     trace_qemu_vfree(ptr); | ||||
|     VirtualFree(ptr, 0, MEM_RELEASE); | ||||
|     if (ptr) { | ||||
|         VirtualFree(ptr, 0, MEM_RELEASE); | ||||
|     } | ||||
| } | ||||
| 
 | ||||
| /* FIXME: add proper locking */ | ||||
|  | ||||
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